The product (B) of the reaction is: | vedclass

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(D) $1$. The first step involves the hydrogenation of the alkene double bond in the cyclohexenone ring using Wilkinson's catalyst,$(Ph_3P)_3RhCl$. Thi

Vedclass · Accepted Answer

$p$-nitrobenzoate ion

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(D) $1$. The first step involves the hydrogenation of the alkene double bond in the cyclohexenone ring using Wilkinson's catalyst,$(Ph_3P)_3RhCl$. This catalyst is selective for the hydrogenation of alkenes without affecting other functional groups like the ester or the nitro group. Thus,$(A)$ is the saturated ester.$2$. The second step is the alkaline hydrolysis (saponification) of the ester $(A)$ using $0.1 \ M \ NaOH$ in aqueous methanol. This reaction cleaves the ester bond to produce the carboxylate salt and the corresponding alcohol.$3$. The carboxylate salt formed is the $p$-nitrobenzoate ion,which is product $(B)$. The other product $(C)$ is the alcohol,which contains no nitrogen.

The product $(B)$ of the reaction is:

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The product $D$ of the reaction is:
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_2O} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$

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